3.108 \(\int \frac {1}{\sqrt {-2+6 x^2-3 x^4}} \, dx\)

Optimal. Leaf size=42 \[ -\frac {F\left (\cos ^{-1}\left (\sqrt {\frac {3}{3+\sqrt {3}}} x\right )|\frac {1}{2} \left (1+\sqrt {3}\right )\right )}{\sqrt {2} \sqrt [4]{3}} \]

[Out]

-1/6*3^(3/4)*(x^2/(3^(1/2)+3))^(1/2)/x*(3^(1/2)+3)^(1/2)*EllipticF((1-3*x^2/(3^(1/2)+3))^(1/2),1/2*(2+2*3^(1/2
))^(1/2))*2^(1/2)

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Rubi [A]  time = 0.05, antiderivative size = 42, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {1095, 420} \[ -\frac {F\left (\cos ^{-1}\left (\sqrt {\frac {3}{3+\sqrt {3}}} x\right )|\frac {1}{2} \left (1+\sqrt {3}\right )\right )}{\sqrt {2} \sqrt [4]{3}} \]

Antiderivative was successfully verified.

[In]

Int[1/Sqrt[-2 + 6*x^2 - 3*x^4],x]

[Out]

-(EllipticF[ArcCos[Sqrt[3/(3 + Sqrt[3])]*x], (1 + Sqrt[3])/2]/(Sqrt[2]*3^(1/4)))

Rule 420

Int[1/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] :> -Simp[EllipticF[ArcCos[Rt[-(d/c), 2]
*x], (b*c)/(b*c - a*d)]/(Sqrt[c]*Rt[-(d/c), 2]*Sqrt[a - (b*c)/d]), x] /; FreeQ[{a, b, c, d}, x] && NegQ[d/c] &
& GtQ[c, 0] && GtQ[a - (b*c)/d, 0]

Rule 1095

Int[1/Sqrt[(a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4], x_Symbol] :> With[{q = Rt[b^2 - 4*a*c, 2]}, Dist[2*Sqrt[-c], I
nt[1/(Sqrt[b + q + 2*c*x^2]*Sqrt[-b + q - 2*c*x^2]), x], x]] /; FreeQ[{a, b, c}, x] && GtQ[b^2 - 4*a*c, 0] &&
LtQ[c, 0]

Rubi steps

\begin {align*} \int \frac {1}{\sqrt {-2+6 x^2-3 x^4}} \, dx &=\left (2 \sqrt {3}\right ) \int \frac {1}{\sqrt {6+2 \sqrt {3}-6 x^2} \sqrt {-6+2 \sqrt {3}+6 x^2}} \, dx\\ &=-\frac {F\left (\cos ^{-1}\left (\sqrt {\frac {3}{3+\sqrt {3}}} x\right )|\frac {1}{2} \left (1+\sqrt {3}\right )\right )}{\sqrt {2} \sqrt [4]{3}}\\ \end {align*}

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Mathematica [B]  time = 0.08, size = 85, normalized size = 2.02 \[ \frac {\sqrt {-3 x^2-\sqrt {3}+3} \sqrt {\left (\sqrt {3}-3\right ) x^2+2} F\left (\sin ^{-1}\left (\sqrt {\frac {1}{2} \left (3+\sqrt {3}\right )} x\right )|2-\sqrt {3}\right )}{\sqrt {6} \sqrt {-3 x^4+6 x^2-2}} \]

Antiderivative was successfully verified.

[In]

Integrate[1/Sqrt[-2 + 6*x^2 - 3*x^4],x]

[Out]

(Sqrt[3 - Sqrt[3] - 3*x^2]*Sqrt[2 + (-3 + Sqrt[3])*x^2]*EllipticF[ArcSin[Sqrt[(3 + Sqrt[3])/2]*x], 2 - Sqrt[3]
])/(Sqrt[6]*Sqrt[-2 + 6*x^2 - 3*x^4])

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fricas [F]  time = 0.87, size = 0, normalized size = 0.00 \[ {\rm integral}\left (-\frac {\sqrt {-3 \, x^{4} + 6 \, x^{2} - 2}}{3 \, x^{4} - 6 \, x^{2} + 2}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-3*x^4+6*x^2-2)^(1/2),x, algorithm="fricas")

[Out]

integral(-sqrt(-3*x^4 + 6*x^2 - 2)/(3*x^4 - 6*x^2 + 2), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {-3 \, x^{4} + 6 \, x^{2} - 2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-3*x^4+6*x^2-2)^(1/2),x, algorithm="giac")

[Out]

integrate(1/sqrt(-3*x^4 + 6*x^2 - 2), x)

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maple [A]  time = 0.02, size = 82, normalized size = 1.95 \[ \frac {2 \sqrt {-\left (-\frac {\sqrt {3}}{2}+\frac {3}{2}\right ) x^{2}+1}\, \sqrt {-\left (\frac {\sqrt {3}}{2}+\frac {3}{2}\right ) x^{2}+1}\, \EllipticF \left (\frac {\sqrt {6-2 \sqrt {3}}\, x}{2}, \frac {\sqrt {6}}{2}+\frac {\sqrt {2}}{2}\right )}{\sqrt {6-2 \sqrt {3}}\, \sqrt {-3 x^{4}+6 x^{2}-2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(-3*x^4+6*x^2-2)^(1/2),x)

[Out]

2/(6-2*3^(1/2))^(1/2)*(-(-1/2*3^(1/2)+3/2)*x^2+1)^(1/2)*(-(1/2*3^(1/2)+3/2)*x^2+1)^(1/2)/(-3*x^4+6*x^2-2)^(1/2
)*EllipticF(1/2*(6-2*3^(1/2))^(1/2)*x,1/2*6^(1/2)+1/2*2^(1/2))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {-3 \, x^{4} + 6 \, x^{2} - 2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-3*x^4+6*x^2-2)^(1/2),x, algorithm="maxima")

[Out]

integrate(1/sqrt(-3*x^4 + 6*x^2 - 2), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {1}{\sqrt {-3\,x^4+6\,x^2-2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(6*x^2 - 3*x^4 - 2)^(1/2),x)

[Out]

int(1/(6*x^2 - 3*x^4 - 2)^(1/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {- 3 x^{4} + 6 x^{2} - 2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-3*x**4+6*x**2-2)**(1/2),x)

[Out]

Integral(1/sqrt(-3*x**4 + 6*x**2 - 2), x)

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